x^2-125x+125=0

Solution for x^2-125x+125=0 equation:

x^2-125x+125=0

a = 1; b = -125; c = +125;
Δ = b2-4ac
Δ = -1252-4·1·125
Δ = 15125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15125}=\sqrt{3025*5}=\sqrt{3025}*\sqrt{5}=55\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-55\sqrt{5}}{2*1}=\frac{125-55\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+55\sqrt{5}}{2*1}=\frac{125+55\sqrt{5}}{2}
$